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2025-pangani-g-chemistry-paper-3-ms

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  • UPLOADED BY Unknown
  • DATE 07 Dec 2025
  • SIZE 1.41 MB
  • DOWNLOADS 0
  • TAGS
    notes
About This Document

Document Type: This is a Solution Set, designed for Verifying answers and correcting mistakes.

Context: Standard material from the 2025 academic period.

Key Content: Likely covers essential definitions, structured questions to test your proficiency.

Study Strategy: Summarize these notes into flashcards or mind maps to aid active recall and long-term retention.

Recommendation: comprehensive resource for students aiming to deepen their understanding of General Studies.

801 words

Detailed Content Overview

5 min read Intermediate Level 801 words
Introduction

This notes resource titled "2025-pangani-g-chemistry-paper-3-ms" offers detailed study notes covering essential concepts and theories. This resource is structured to facilitate effective learning and retention of important information.

Key Topics Covered
1 Principles of averaging
Learning Objectives
  • Understand fundamental principles and core concepts
  • Build a strong foundation for advanced study
  • Connect theoretical knowledge with practical applications
  • Prepare comprehensively for assessments and exams
Detailed Summary

TERM 2 2025 MARKING SCHEME CHEMISTRY PAPER 3 (a) Time (min) Temperature (oC ) Download this and other FREE materials from https://teacher. 0 – 1mk - 8 readings – 1mk- penalize – ½ of space not filled - ½ for unrealistic values T 100 or 40 - ½ all constant t = 0 to t = 4 - ½ if T( T(2 ½ ) Decimal place – 1mk - Accept whole number or to 1d. C = 1 Tr = 1 4mks (i) T = correct reading (ii) Heat of solution = MCT = 50g x 4. 0238 = -Ans Penalized if H – sign is + and not – ve (total 3mks) TABLE 2 Titre I II III Download this and other FREE revision materials from https://teacher. ke/notes Download this and other FREE materials from https://teacher. ke/notes Final burette reading 24. 0 3 Volume of solution H used (cm ) 24. 3 Conditions:- A complete table. T = 1 3 consistent titrations 1ms D. C = 1 2 titrations done and are consistent. 1mk AC = 1 3 inconsistent titrations done and averaged 0mk PA = 1 only 1 titration done. 0mk GFA= 1 5mks Penalty: (i) Penalize ½mk for inverted table.

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Content Preview

TERM 2 2025 MARKING SCHEME CHEMISTRY PAPER 3 (a) Time (min) Temperature (oC ) Download this and other FREE materials from https://teacher.co.ke/notes 1. (b) (b) 0 19.0 ½ 19.0 1 19.0 1½ 19.0 2 X 2½ 16.0 Complete 3 15.0 3½ 15.0 – 1mk - 8 readings – 1mk- penalize – ½ of space not filled - ½ for unrealistic values T 100 or 40 - ½ all constant t = 0 to t = 4 - ½ if T( T(2 ½ ) Decimal place – 1mk - Accept whole number or to 1d.p of 0.5 or 0.0 Accuracy – 1mk S.V  2units Trend – 1mk Award ½ - where t =...

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