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2025-muranga-east-chemistry-pp3-scheme

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  • UPLOADED BY Unknown
  • DATE 07 Dec 2025
  • SIZE 1.63 MB
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About This Document

Document Type: This is a Assessment, designed for Evaluating understanding of key concepts.

Context: Standard material from the 2025 academic period.

Key Content: Likely covers essential definitions, structured questions to test your proficiency.

Study Strategy: Summarize these notes into flashcards or mind maps to aid active recall and long-term retention.

Recommendation: comprehensive resource for students aiming to deepen their understanding of General Studies.

820 words

Detailed Content Overview

5 min read Intermediate Level 820 words
Introduction

This notes resource titled "2025-muranga-east-chemistry-pp3-scheme" provides comprehensive exam preparation materials designed to test and enhance your understanding. This resource is structured to facilitate effective learning and retention of important information.

Key Topics Covered
1 Download this and other FREE materials from https://teacher.co.ke/notes Table 1
2 You are provided with solid X which is a mixture of two compounds, carry out the
Learning Objectives
  • Understand fundamental principles and core concepts
  • Build a strong foundation for advanced study
  • Connect theoretical knowledge with practical applications
  • Prepare comprehensively for assessments and exams
Detailed Summary

1 CHEM PAPER 3 MARKING SCHEME Question 1 Download this and other FREE materials from https://teacher. ke/notes Table 1 1 2 3 Final burette reading(cm3) 24. 0 Volume of acid used (cm3) 24. 5 Marking - Complete table award; ✓ - Decimal consistency; ✓ - Accuracy  0. 1;✓ - School value; ✓ Principles of averaging: Average volume = 24. 5 cm3; ✓(½ mark) (a) Moles of sodium hydroxide used Molarity of solution: Moles = Mass /litre RMM = 4 = 0. 0025 moles; 1000 Download this and other FREE revision materials from https://teacher. ke/notes 2 (ii) Moles of hydrochloric acid NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l) Download this and other FREE materials from https://teacher. ke/notes Mole ratio = 1:1; Thus moles of acid = 0. 0025 moles; (iii) Molarity of acid. Volume of acid reacting = average titre in (a) e. 5 i) Volume of distilled water in Temperature in 0C at which Solution of solid C in the boiling tube cm3. 50 a) Complete the table by calculating the solubility of solid C in g/100g of water.

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Content Preview

1 CHEM PAPER 3 MARKING SCHEME Question 1 Download this and other FREE materials from https://teacher.co.ke/notes Table 1 1 2 3 Final burette reading(cm3) 24.5 24.5 24.5 Initial burette reading (cm3) 0.0 0.0 0.0 Volume of acid used (cm3) 24.5 24.5 24.5 Marking - Complete table award; ✓ - Decimal consistency; ✓ - Accuracy  0.1;✓ - School value; ✓ Principles of averaging: Average volume = 24.5 + 24.5 + 24.5 = 24.5; ✓ (½ mark) 3 = 24.5 cm3; ✓(½ mark) (a) Moles of sodium hydroxide used Molarity of s...

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