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mathematics-end-f4t2-pp2-ms

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  • DATE 07 Dec 2025
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About This Document

Document Type: This is a Study Notes, designed for Reviewing core curriculum material.

Context: Core educational material suitable for current academic requirements.

Key Content: Likely covers essential definitions, problem solving, and structured questions to test your proficiency.

Study Strategy: Summarize these notes into flashcards or mind maps to aid active recall and long-term retention.

Recommendation: comprehensive resource for students aiming to deepen their understanding of General Studies.

479 words

Detailed Content Overview

3 min read Intermediate Level 479 words
Introduction

This notes resource titled "mathematics-end-f4t2-pp2-ms" offers detailed study notes covering essential concepts and theories. This resource is structured to facilitate effective learning and retention of important information.

Key Topics Covered
1 Problem Solving Techniques
2 Mathematical Concepts
3 Practical Applications
Learning Objectives
  • Understand fundamental principles and core concepts
  • Build a strong foundation for advanced study
  • Connect theoretical knowledge with practical applications
  • Prepare comprehensively for assessments and exams
Detailed Summary

MATHEMATICS FORM FOUR PAPER 2 MARKING SCHEME No Working 1 Download this and other FREE materials from https://teacher. 125 ๐‘๐‘š2 2 Marks B1 for all logs B1 for correct addition M1 A1 M1 1 Minimum area = ร— 11. 2 ๐‘ฅ 2 + ๐‘ฆ 2 โˆ’ 4๐‘ฅ + 6๐‘ฆ = 3 (๐‘ฅ โˆ’ 2)2 + (๐‘ฆ + 3)2 = 3 + 4 + 9 5 6 7 (๐‘ฅ โˆ’ 2)2 + (๐‘ฆ + 3)2 = 42 B1 Centre (2,-3) M1 ๐‘Ÿ๐‘Ž๐‘‘๐‘–๐‘ข๐‘  = 4 A1 ๐‘Ž๐‘›๐‘”๐‘™๐‘’ = 100ยฐ 100 ร— 60 = 6000 6000 = 20 hrs 300 1 ๐‘Ž๐‘Ÿ 5 11 4 = 1 ๐‘Ž๐‘Ÿ 2 3 3 3 3 ๐‘Ÿ =3 8 1 ๐‘Ÿ=1 2 9 10 ๐‘Ž. ( ) = 4 2 13 ๐‘Ž=1 27 log ๐‘ฆ = nlog ๐‘ฅ + log ๐‘Ž B1 M1 A1 M1 A1 A1 M1 Download this and other FREE revision materials from https://teacher. 01 ๐‘›= 8 A1 0 โˆ’ โˆ’2 2 = 5โˆ’0 5 ๐‘ฆ๐‘–๐‘’๐‘™๐‘‘๐‘  M1 A1 ๐ถ = ๐ดโˆ’1 ๐ต ๐ด๐ถ = ๐ต โ†’ 2 3 ๐‘Ž ๐‘ โˆ’1 3 )( )=( ) 1 4 ๐‘ ๐‘‘ 2 โˆ’1 1 4 โˆ’3 2 3 ๐‘Ž ๐‘ 1 4 ( )( )( )= ( 1 4 ๐‘ ๐‘‘ 5 โˆ’1 2 5 โˆ’1 โˆ’2 3 ) ๐ถ=( 1 โˆ’1 ๐‘˜ ๐‘ƒ=๐ถ+ 2 ๐‘ก ๐‘˜ 6=๐ถ+ 2 6 ๐‘˜ 18 = ๐ถ + 9 9 Download this and other FREE materials from https://teacher. ke/notes ( M1 โˆ’3 โˆ’1 )( 2 2 3 ) โˆ’1 M1 A1 M1 ๐‘˜ = 144 ๐‘Ž๐‘›๐‘‘ ๐ถ = 2 M1 When P = 11 11 = 2 + 144 ๐‘ก2 ๐‘ก 2 = 16 A1 ๐‘ก = ยฑ4 10 1750 ร— 24 = 42000 42000 = 30000 (1 + M1 ๐‘Ÿ ) 100 24 ๐‘Ÿ 24 ) 100 M1 โˆš1. 41 11 log 3 ๐‘ฅ 3 + log 3 81 = log 3 24 M1 log 3 (๐‘ฅ 3 ร— 81) = log 3( 24) 81๐‘ฅ 3 = 24 M1 2 3 A1 ๐‘ฅ= Download this and other FREE revision materials from https://teacher. ke/notes 12 6(1 โˆ’ ๐‘๐‘œ๐‘  2 ๐‘ฅ) โˆ’ ๐‘๐‘œ๐‘ ๐‘ฅ โˆ’ 5 = 0 Let cos ๐‘ฅ = ๐‘ 6๐‘2 + ๐‘ โˆ’ 1 = 0 3๐‘(2๐‘ + 1) โˆ’ 1(2๐‘ + 1) = 0 1 1 ๐‘ = ๐‘œ๐‘Ÿ โˆ’ 3 2 1 When ๐‘ = , values of ๐‘ฅ = 70. 5 3 M1 M1 A1 for the two expression 1 13 Download this and other FREE materials from https://teacher. ke/notes ๐‘คโ„Ž๐‘’๐‘› ๐‘ = โˆ’ , values of ๐‘ฅ = 120, 240 2 2 3 5 5 Cost of mixture = ( ร— 160) + ( ร— 140) = ๐‘†โ„Ž. 162% det โŸน (3 ร— 4) โˆ’ (1 ร— 5) = 7 7= M1 B1 140 ๐‘ฅ M1 A1 ๐‘ฅ = 20 15 i. 898 A1 โˆš3 2 B1 1 tan ๐‘ฅ + cos ๐‘ฅ = โŸน โˆš3 + โˆš3 2 2 + โˆš9 2โˆš3 2โˆš3 ร— 2โˆš3 2โˆš3 5โˆš3 6 a) M1 5 17 A1 B1 B1 2 20 3 100 b) (i) ( ร— 2 20 3 100 2 4 1 3 5 10 (ii) ( ร— (iii) ( ร— ร— 1 10 3 100 )+( ร— ร— 3 1 10 3 100 )+( ร— 10 )= 1 9 3 10 )+( ร— ร— 1 6 ร— 7 M1 A1 3 )= 10 )= 10 1 25 M1 A1 79 300 Download this and other FREE revision materials from https://teacher.

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MATHEMATICS FORM FOUR PAPER 2 MARKING SCHEME No Working 1 Download this and other FREE materials from https://teacher.co.ke/notes No 415.3 0.0152 Standard form 4.153 ร— 102 1.52 ร— 10โˆ’2 sin 75 100.2717 = 1.869 2 โ† Log 2.6183 2ฬ…. 1818 + ๐ŸŽ. ๐Ÿ–๐ŸŽ๐ŸŽ๐Ÿ 1ฬ…. 9849 โˆ’ 0.8152 รท 3 0.2717 1 Maximum area = ร— 12.5 ร— 8.5 = 53.125 ๐‘๐‘š2 2 Marks B1 for all logs B1 for correct addition M1 A1 M1 1 Minimum area = ร— 11.5 ร— 7.5 = 43.125 ๐‘๐‘š2 Absolute error = 3 2 M1 53.125โˆ’43.125 2 =5 A1 2 5 810 1080 720 240 (3 + ) = 243 + + 2...

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