mathematics-f3t1-2024-ms-teacher.co_.ke
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DATE 07 Dec 2025
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About This Document
Document Type: This is a Study Notes, designed for Reviewing core curriculum material.
Context: Standard material from the 2024 academic period.
Key Content: Likely covers essential definitions, problem solving, and theoretical concepts necessary for mastery of the subject.
Study Strategy: Summarize these notes into flashcards or mind maps to aid active recall and long-term retention.
Recommendation: comprehensive resource for students aiming to deepen their understanding of General Studies.
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Introduction
This notes resource titled "mathematics-f3t1-2024-ms-teacher.co_.ke" offers detailed study notes covering essential concepts and theories. This resource is structured to facilitate effective learning and retention of important information.
Key Topics Covered
Learning Objectives
- Understand fundamental principles and core concepts
- Build a strong foundation for advanced study
- Connect theoretical knowledge with practical applications
- Prepare comprehensively for assessments and exams
Detailed Summary
MARKING SCHEME Download this and other FREE materials from https://teacher. ke/notes No 1 2 3 4 5 6 7 8 9 Working 2 5 5 3 ๐โ + โ = 3 6 4 12 2 9 8 3 8 5 ๐ทโ ร โ = โ = 3 4 7 2 7 4 ๐ 3 5 7 = รท = ๐ท 12 14 10 3(3 + โ7) โ โ7(3 + โ3) = 2 2 3 โ โ7 = โ 2 3 + โ7 = 2(3 + โ7) โ 2(3 โ โ7) 2 4โ7 = 2โ7 2 M1 A1 M1 M1 A1 2๐ฅ ร 3๐ฆ = 4 ร 27 2๐ฅ = 22 โ ๐ฅ = 2 3๐ฆ = 33 โ ๐ฆ = 3 Area of rhombus = 2 ร 0. 8 โ 5432 ๐๐๐๐๐๐๐ Total time = 30 mins + 2 hrs + 4 hrs = 6 โ๐ 30 ๐๐๐ Arrival time = 10: 00 ๐. 7 000 (a) 3 โ 2๐ฅ < ๐ฅ โ 3 and ๐ฅ โ 3 โค 4 (๐) 6 < 3๐ฅ โ ๐ฅ > 2 ๐ฅ โค4+3โ๐ฅ โค7 (c) integral values = 3,4,5,6 ๐๐๐ 7 8โ6 ๐1 = =1 4โ2 ๐2 = โ1 Mid point of AB = Marks M1 M1 M1 A1 M1 M1 A1 M1 A1 M1 A1 M1 A1 M1 M1 A1 B1 B1 B1 B1 M1 M1 2+4 6+8 2 , 2 = 3,7 ๐ฆโ7 = โ1 ๐ฅโ3 ๐ฆ = โ๐ฅ + 10 A1 Download this and other FREE revision materials from https://teacher. ke/notes 10 (2๐)90 4 = (2๐ โ 4)90 3 M1 Download this and other FREE materials from https://teacher. ke/notes 6๐ = 8๐ โ 16 11 12 13 14 ๐=8 M1 Sum = (2(8) โ 4)90 = 1080ยฐ A1 log 5 5 + log 5 ๐ฅ = log 5 12 M1 5๐ฅ = 12 ๐ฅ= 12 = 2. 4 5 M1 A1 152 = 92 + ๐ 2 M1 ๐ = โ144 = 12 ๐๐ Volume of cone = 3 ร 7 ร 12 ร 12 ร 9 = 1357. 28 ๐๐2 M1 A1 M1 22 Maximum volume = 7 ร 4. 38% 16 2 3๐ฅ โ ๐ฅ โ 7 = 0 โ(โ1) ยฑ โ1 โ (4 ร 3 ร โ7) ๐ฅ= 2(3) M1 A1 M1 M1 Download this and other FREE revision materials from https://teacher. 37 (a) < ๐ = 430 (subtended by chordAB) < ๐ = 400 < ๐ = 250 (subtended by chord DC) < ๐ = 180 โ 40 + 25 + 43 + 40 = 32ยฐ A1 B1 B1 B1 B1 (b) 180ยฐ โ 80ยฐ = 100ยฐ 2๐ฅ = 100ยฐ ๐ฅ = 500 B1 B1 ๐ฆ + 70 = 1800 ๐ฆ = 1100 B1 B1 ๐ฅ= Download this and other FREE materials from https://teacher. ke/notes 17 18 222 (c) โ ๐ฅ = 360ยฐ โ 138ยฐ = 2 = 1110 (i) 92 + 102 โ 2(9)(10) cos ๐ = 122 ๐ป๐๐๐๐ cos ๐ = 37 180 B1 B1 M1 M1 A1 ๐ = 78.
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MARKING SCHEME Download this and other FREE materials from https://teacher.co.ke/notes No 1 2 3 4 5 6 7 8 9 Working 2 5 5 3 ๐โ + โ = 3 6 4 12 2 9 8 3 8 5 ๐ทโ ร โ = โ = 3 4 7 2 7 4 ๐ 3 5 7 = รท = ๐ท 12 14 10 3(3 + โ7) โ โ7(3 + โ3) = 2 2 3 โ โ7 = โ 2 3 + โ7 = 2(3 + โ7) โ 2(3 โ โ7) 2 4โ7 = 2โ7 2 M1 A1 M1 M1 A1 2๐ฅ ร 3๐ฆ = 4 ร 27 2๐ฅ = 22 โ ๐ฅ = 2 3๐ฆ = 33 โ ๐ฆ = 3 Area of rhombus = 2 ร 0.5 ร 9 ร 9 ร sin 60 = 70.14 ๐๐2 60 22 Area of sector = 360 ร 7 ร 81 = 42.43 ๐๐2 Area of shaded region = 70.14 โ 42.43 = 27...
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